0.25n^2+0.75n-600=0

Solution for 0.25n^2+0.75n-600=0 equation:

0.25n^2+0.75n-600=0

a = 0.25; b = 0.75; c = -600;
Δ = b2-4ac
Δ = 0.752-4·0.25·(-600)
Δ = 600.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.75)-\sqrt{600.5625}}{2*0.25}=\frac{-0.75-\sqrt{600.5625}}{0.5}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.75)+\sqrt{600.5625}}{2*0.25}=\frac{-0.75+\sqrt{600.5625}}{0.5}
$